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For the synthesis of one glucose molecule the Calvin cycle operates for :
A
2 times
B
4 times
C
6 times
D
8 times
Detailed Solution
Each turn of the Calvin cycle fixes one molecule of $CO_2$.
Glucose ($C_6H_{12}O_6$) has six carbon atoms, so six $CO_2$ molecules must be fixed.
So the Calvin cycle operates 6 times for one glucose molecule, using 18 ATP and 12 NADPH.
Glucose ($C_6H_{12}O_6$) has six carbon atoms, so six $CO_2$ molecules must be fixed.
So the Calvin cycle operates 6 times for one glucose molecule, using 18 ATP and 12 NADPH.