2004 AIPMT Respiration in PlantsGlycolysis Easy Question 5 of 5 in Glycolysis

In glycolysis, during oxidation electrons are removed by -

A Glyceraldehyde-3-phosphate
B $NAD^+$
C Molecular oxygen
D ATP

The answer is B.

Solution

Glycolysis breaks one glucose into two molecules of pyruvic acid in the cytoplasm.
The only oxidation step is the conversion of glyceraldehyde-3-phosphate (PGAL) into 1,3-bisphosphoglycerate.
In this step, two electrons and a proton (a hydride ion) are removed from PGAL and accepted by the coenzyme $NAD^+$, which is reduced to $NADH + H^+$:
$PGAL + NAD^+ + P_i \rightarrow 1,3\text{-}BPGA + NADH + H^+$
Glyceraldehyde-3-phosphate is the compound being oxidised, not the electron acceptor. Molecular oxygen is not used in glycolysis (it is the final acceptor only in the electron transport chain).
So in glycolysis electrons are removed by $NAD^+$.

Concept NAD+ as electron acceptor in glycolysis

Glycolysis in past papers

5 questions from this chapter have appeared across 5 exam years.