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The major products C and D formed in the following reactions respectively are:
$H_3C-CH_2-CH_2-O-C(CH_3)_3\xrightarrow[\Delta]{excess\ HI}C+D$
Detailed Solution
The ether cleaves via the stable tertiary carbocation to give $CH_3CH_2CH_2OH+(CH_3)_3C-I$. With excess HI the propanol is further converted to $CH_3CH_2CH_2-I$. So C and D are $CH_3CH_2CH_2I$ and $(CH_3)_3CI$.