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$CH_3CH_2CH=CH_2\xrightarrow[(ii)\ H_2O_2,\ OH^-]{(i)\ B_2H_6}Z$. What is Z?
A
$CH_3CH_2CH_2CH_3$
B
$CH_3CH_2CH_2CH_2OH$
C
$CH_3CH_2CH(OH)CH_3$
D
$CH_3CH_2CH_2$(radical, incomplete)
Detailed Solution
Hydroboration-oxidation follows anti-Markovnikov addition: boron attaches to the less substituted (terminal) carbon, and subsequent oxidation with $H_2O_2/OH^-$ replaces the C-B bond with a C-OH bond. So 1-butene gives the primary alcohol $CH_3CH_2CH_2CH_2OH$ (n-butanol).