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Consider the following reaction: 
'A'. The product 'A' is
'A'. The product 'A' is
A
$C_6H_5Cl$
B
$C_6H_5CHO$
C
$C_6H_5OH$
D
$C_6H_5COCH_3$
Detailed Solution
An acid chloride is reduced by $H_2$ over palladium supported on $BaSO_4$ to an aldehyde. This is the Rosenmund reduction.
$BaSO_4$ poisons the catalyst so that the aldehyde is not reduced further to the alcohol.
So A is benzaldehyde, $C_6H_5CHO$.
$BaSO_4$ poisons the catalyst so that the aldehyde is not reduced further to the alcohol.
So A is benzaldehyde, $C_6H_5CHO$.