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In the reaction
A is
A is
A
$H^+/H_2O$
B
$HgSO_4/H_2SO_4$
C
$Cu_2Cl_2$
D
$H_3PO_2$ and $H_2O$
Detailed Solution
$H_3PO_2/H_2O$ reduces the diazonium group, replacing $-N_2^+Cl^-$ by H.
