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What is the product obtained in the following reaction?
A
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B
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C
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D
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Detailed Solution
The product of reduction of nitrobenzene depends on the medium.
In acidic medium (Sn/HCl or Fe/HCl) nitrobenzene is reduced completely to aniline, $C_6H_5NH_2$.
In neutral medium (Zn dust with aqueous $NH_4Cl$) the reduction stops at the hydroxylamine stage:
In alkaline medium, bimolecular products such as azoxybenzene, azobenzene and hydrazobenzene are formed.
Hence the product with $Zn/NH_4Cl$ is N-phenylhydroxylamine, $C_6H_5NHOH$.
In acidic medium (Sn/HCl or Fe/HCl) nitrobenzene is reduced completely to aniline, $C_6H_5NH_2$.
In neutral medium (Zn dust with aqueous $NH_4Cl$) the reduction stops at the hydroxylamine stage:
In alkaline medium, bimolecular products such as azoxybenzene, azobenzene and hydrazobenzene are formed.
Hence the product with $Zn/NH_4Cl$ is N-phenylhydroxylamine, $C_6H_5NHOH$.