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Which of the following plot represents the variation of $\ln k$ versus $\dfrac{1}{T}$ in accordance with Arrhenius equation? [add image: four graph options (a)-(d)]
A
[add image: ln k increasing with 1/T, positive slope]
B
[add image: ln k increasing steeply with 1/T]
C
[add image: ln k decreasing linearly with 1/T]
D
[add image: ln k increasing with 1/T, different intercept]
Detailed Solution
Arrhenius equation: $k=Ae^{-E_a/RT}\Rightarrow\ln k=\ln A-\dfrac{E_a}{R}\cdot\dfrac{1}{T}$. This is a straight line ($y=mx+c$) with slope $m=-\dfrac{E_a}{R}$ (negative) and intercept $\ln A$, i.e. $\ln k$ decreases linearly as $1/T$ increases.