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The decomposition of phosphine ($PH_3$) on tungsten at low pressure is a first-order reaction. It is because the
A
rate is independent of the surface coverage
B
rate of decomposition is very slow
C
rate is proportional to the surface coverage
D
rate is inversely proportional to the surface coverage
Explanation
At low pressure coverage ∝ pressure, so rate is first order.
Detailed Solution
The decomposition of $PH_3$ on tungsten at low pressure is first order because the rate is proportional to the surface coverage.
