The decomposition of phosphine (PH₃) on tungsten at low pressure is a first-order reaction. It is because the

The decomposition of phosphine ($PH_3$) on tungsten at low pressure is a first-order reaction. It is because the
A rate is independent of the surface coverage
B rate of decomposition is very slow
C rate is proportional to the surface coverage
D rate is inversely proportional to the surface coverage

Explanation

At low pressure coverage ∝ pressure, so rate is first order.

Detailed Solution

The decomposition of $PH_3$ on tungsten at low pressure is first order because the rate is proportional to the surface coverage.

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