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$2A\xrightarrow{k}B$ is a zero-order reaction, where k = 1.0 mol L$^{-1}$ min$^{-1}$. If the initial concentration of A is 2 M, then the time taken to complete 75% of the reaction will be
Detailed Solution
$2A\xrightarrow{k}B$, zero order: rate $=\frac{1}{2}\left(-\frac{d[A]}{dt}\right)=k \Rightarrow -\frac{d[A]}{dt}=2k \Rightarrow [A]_0-[A]_t=2kt$. For 75% completion, $[A]_t=0.25\times2=0.5$ M: $2-0.5=2(1)t_{75\%} \Rightarrow t_{75\%}=0.75$ min.