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Match the coordination number and type of hybridisation with distribution of hybrid orbitals in space based on Valence bond theory.
Column I
- a. 4, sp3
- b. 4, dsp2
- c. 5, sp3d
- d. 6, d2sp3
Column II
- i. trigonal bipyramidal
- ii. octahedral
- iii. tetrahedral
- iv. square planar
Correct answer: a → iii, b → iv, c → i, d → ii
Detailed Solution
4, $sp^3$ hybridisation gives tetrahedral geometry (a-iii); 4, $dsp^2$ hybridisation gives square planar geometry (b-iv); 5, $sp^3d$ hybridisation gives trigonal bipyramidal geometry (c-i); 6, $d^2sp^3$ hybridisation gives octahedral geometry (d-ii).