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The correct order of the stoichiometries of AgCl formed when $AgNO_3$ in excess is treated with the complexes: $CoCl_3\cdot6NH_3$, $CoCl_3\cdot5NH_3$, $CoCl_3\cdot4NH_3$ respectively is
Explanation
Only counter-ion chlorides precipitate with $AgNO_3$.
Detailed Solution
The complexes are respectively $[Co(NH_3)_6]Cl_3$, $[Co(NH_3)_5Cl]Cl_2$ and $[Co(NH_3)_4Cl_2]Cl$.
Only ionisable (outside-sphere) $Cl^-$ precipitates as AgCl: 3, 2 and 1 respectively.