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An excess of $AgNO_3$ is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium(III) chloride. The number of moles of AgCl precipitated would be:
A
0.01
B
0.001
C
0.002
D
0.003
Detailed Solution
The complex is $[Cr(H_2O)_4Cl_2]Cl$, which has one ionisable chloride ion per formula unit.
Moles of complex $= 0.1\ L\times0.01\ M = 0.001$ mol
So 0.001 mol of AgCl is precipitated.
Moles of complex $= 0.1\ L\times0.01\ M = 0.001$ mol
So 0.001 mol of AgCl is precipitated.
