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A solution of copper sulphate is electrolysed for 10 minutes with a current of 1.5 amperes. The mass of copper deposited at cathode is: [Given: Molar mass of Cu = 63 g $mol^{-1}$; 1 F = 96487 C $mol^{-1}$]
A
2.4036 g
B
1.7018 g
C
0.5876 g
D
0.2938 g
Detailed Solution
$w = \frac{E}{96500} \times I \times t$
$w = \frac{63}{2 \times 96500} \times 1.5 \times 10 \times 60$
$w = 0.293$ g