Looking for classes? Ksquare Career Institute, Bengaluru →
Electrochemistry
Kohlrausch's Law
7 questions, each with its answer.
-
Following limiting molar conductivities are given as $\lambda^0_{m(H_2SO_4)}=x$ S cm$^2$ mol$^{-1}$, $\lambda^0_{m(K_2SO_4)}=y$ S cm$^2$ mol$^{-1}$, $\lambda^0_{m(CH_3COOK)}=z$ S cm$^2$ mol$^{-1}$ $\lambda^0_m$ (in S cm$^2$ mol$^{-1}$) for $CH_3COOH$ will be:By Kohlrausch's law, $\lambda^0_{CH_3COOH}=\lambda^0_{CH_3COO^-}+\lambda^0_{H^+}=\lambda^0_{CH_3COOK}+\frac{1}{2}\lambda^0_{H_2SO_4}-\frac{1}{2}\lambda^0_{K_2SO_4}=z+\frac{x}{2}-\frac{y}{2}=\frac{(x-y)}{2}+z$.
That is every medium question from 2019 Odisha in Kohlrausch's Law.
Show all 7 questions Next: Conductance of Electrolytic Solutions – Ostwald's Dilution
Want a score?
Answers here are not saved. Practise as a test to be marked and see your progress.
Practise as a test