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The molar conductivity of a 0.5 mol/$dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3}\ S\ cm^{-1}$ at 298 K is
A
0.086 S $cm^2$/mol
B
28.8 S $cm^2$/mol
C
2.88 S $cm^2$/mol
D
11.52 S $cm^2$/mol
Explanation
$\Lambda_m = 1000\kappa/C$.
Detailed Solution
C = 0.5 mol/$dm^3$, $\kappa = 5.76\times10^{-3}\ S\ cm^{-1}$, T = 298 K
$\lambda_m = \frac{\kappa\times1000}{M} = \frac{5.76\times10^{-3}\times1000}{0.5} = 11.52\ S\ cm^2/mol$
$\lambda_m = \frac{\kappa\times1000}{M} = \frac{5.76\times10^{-3}\times1000}{0.5} = 11.52\ S\ cm^2/mol$