Looking for classes? Ksquare Career Institute, Bengaluru →
Conjugate acid of $NH_2^-$ :
A
$NH_4OH$
B
$NH_4^+$
C
$NH^{2-}$
D
$NH_3$
Detailed Solution
A conjugate acid is formed when a base accepts one proton ($H^+$).
$NH_2^- + H^+ \rightarrow NH_3$
So the conjugate acid of the amide ion $NH_2^-$ is $NH_3$. ($NH_4^+$ is the conjugate acid of $NH_3$, and $NH^{2-}$ is the conjugate base of $NH_2^-$.)
$NH_2^- + H^+ \rightarrow NH_3$
So the conjugate acid of the amide ion $NH_2^-$ is $NH_3$. ($NH_4^+$ is the conjugate acid of $NH_3$, and $NH^{2-}$ is the conjugate base of $NH_2^-$.)