The equilibrium concentrations of the species in the reaction A+B⇌ C+D are 2, 3, 10 and 6 mol L⁻¹ respectively…

The equilibrium concentrations of the species in the reaction $A+B\rightleftharpoons C+D$ are 2, 3, 10 and 6 mol $L^{-1}$ respectively at 300 K. $\Delta G^0$ for the reaction is (R = 2 cal/mol K)
A -13.73 cal
B 1372.60 cal
C -137.26 cal
D -1381.80 cal

Explanation

$K_{eq}=10$ and $\Delta G^0=-2.303RT\log K_{eq}=-1381.8$ cal.

Detailed Solution

$K_{eq}=\frac{[C][D]}{[A][B]}=\frac{10\times6}{2\times3}=10$ $\Delta G^0=-2.303\,RT\log K_{eq}=-2.303(2)(300)(\log10)=-1381.8$ cal ($\because R=2$ cal/mol K)

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