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The equilibrium concentrations of the species in the reaction $A+B\rightleftharpoons C+D$ are 2, 3, 10 and 6 mol $L^{-1}$ respectively at 300 K. $\Delta G^0$ for the reaction is (R = 2 cal/mol K)
A
-13.73 cal
B
1372.60 cal
C
-137.26 cal
D
-1381.80 cal
Explanation
$K_{eq}=10$ and $\Delta G^0=-2.303RT\log K_{eq}=-1381.8$ cal.
Detailed Solution
$K_{eq}=\frac{[C][D]}{[A][B]}=\frac{10\times6}{2\times3}=10$
$\Delta G^0=-2.303\,RT\log K_{eq}=-2.303(2)(300)(\log10)=-1381.8$ cal ($\because R=2$ cal/mol K)
