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Reaction $BaO_2(s) \rightleftharpoons BaO(s) + O_2(g)$; $\Delta H$ = +ve. In equilibrium condition, pressure of $O_2$ depends on : -
A
Increase mass of $BaO_2$
B
Increase mass of BaO
C
Increase temp. on Eqm.
D
Increase mass of $BaO_2$ and BaO both
The answer is C.
