Looking for classes? Ksquare Career Institute, Bengaluru →
The correct order of solubility of the given salts in water at 298 K is
AgBr: $K_{sp}=5.0\times10^{-13}$; $Zn(OH)_2$: $K_{sp}=1.0\times10^{-15}$; $Hg_2Cl_2$: $K_{sp}=1.3\times10^{-18}$
Detailed Solution
AgBr: $K_{sp}=s^2 \Rightarrow s_1=\sqrt{5\times10^{-13}}=7.1\times10^{-7}$ M. $Zn(OH)_2$: $K_{sp}=4s^3 \Rightarrow s_2=\left(\frac{1.0\times10^{-15}}{4}\right)^{1/3}=6.3\times10^{-6}$ M. $Hg_2Cl_2\rightarrow Hg_2^{2+}+2Cl^-$: $K_{sp}=4s^3 \Rightarrow s_3=\left(\frac{1.3\times10^{-18}}{4}\right)^{1/3}=6.9\times10^{-7}$ M. Order of solubility: $Zn(OH)_2>AgBr>Hg_2Cl_2$.