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Solubility of a $M_2S$ salt is $3.5 \times 10^{-6}$ then find out solubility product : -
A
$1.7 \times 10^{-6}$
B
$1.7 \times 10^{-16}$
C
$1.7 \times 10^{-18}$
D
$1.7 \times 10^{-12}$
Detailed Solution
$M_2S \rightleftharpoons 2M^+ + S^{2-}$. If the solubility is s, then $[M^+] = 2s$ and $[S^{2-}] = s$.
$K_{sp} = (2s)^2(s) = 4s^3$
$K_{sp} = 4 \times (3.5 \times 10^{-6})^3 = 4 \times 42.875 \times 10^{-18}$
$K_{sp} = 1.715 \times 10^{-16} \approx 1.7 \times 10^{-16}$
$K_{sp} = (2s)^2(s) = 4s^3$
$K_{sp} = 4 \times (3.5 \times 10^{-6})^3 = 4 \times 42.875 \times 10^{-18}$
$K_{sp} = 1.715 \times 10^{-16} \approx 1.7 \times 10^{-16}$