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The major product C in the below mentioned reaction is: $CH_3CH_2CH_2Br\xrightarrow[\Delta]{alc.\ KOH}A\xrightarrow{HBr}B\xrightarrow[\Delta]{alc.\ KOH}C$
A
Propan-1-ol
B
Propan-2-ol
C
Propane
D
Propyne
Detailed Solution
$CH_3CH_2CH_2Br\xrightarrow{alc.\ KOH,\Delta}CH_3CH=CH_2$ (A, propene, by dehydrohalogenation); $CH_3CH=CH_2\xrightarrow{HBr}CH_3CHBrCH_3$ (B, 2-bromopropane, by Markovnikov addition); $CH_3CHBrCH_3\xrightarrow{alc.\ KOH,\Delta}$ double dehydrohalogenation gives propyne (C).
