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Elimination reaction of 2-Bromo-pentane to form pent-2-ene is:
(a) $\beta$-Elimination reaction
(b) Follows Zaitsev rule
(c) Dehydrohalogenation reaction
(d) Dehydration reaction
A
(a), (c), (d)
B
(b), (c), (d)
C
(a), (b), (d)
D
(a), (b), (c)
Detailed Solution
$CH_3-CH(Br)-CH_2-CH_2-CH_3 \xrightarrow{base} CH_3-CH=CH-CH_2-CH_3$
A $\beta$-hydrogen is abstracted, so it is a $\beta$-elimination reaction.
The more substituted alkene (pent-2-ene) is formed, so it follows Zaitsev's rule.
H and Br are removed, so it is a dehydrohalogenation reaction (not dehydration).
So (a), (b) and (c) are correct.