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In the reaction, $H-C\equiv CH \xrightarrow[(ii)\ CH_3CH_2Br]{(i)\ NaNH_2/liq.NH_3} X \xrightarrow[(ii)\ CH_3CH_2Br]{(i)\ NaNH_2/liq.NH_3} Y$, X and Y are
A
X = 2-butyne ; Y = 3-hexyne
B
X = 2-butyne ; Y = 2-hexyne
C
X = 1-butyne ; Y = 2-hexyne
D
X = 1-butyne ; Y = 3-hexyne
Explanation
Two successive ethylations of acetylene.
Detailed Solution
$HC\equiv CH \xrightarrow{NaNH_2/liq.NH_3} HC\equiv C^-Na^+ \xrightarrow{CH_3CH_2Br} CH_3CH_2C\equiv CH$ (X = but-1-yne)
$CH_3CH_2C\equiv CH \xrightarrow{NaNH_2/liq.NH_3} CH_3CH_2C\equiv C^-Na^+ \xrightarrow{CH_3CH_2Br} CH_3CH_2C\equiv CCH_2CH_3$ (Y = hex-3-yne)
$CH_3CH_2C\equiv CH \xrightarrow{NaNH_2/liq.NH_3} CH_3CH_2C\equiv C^-Na^+ \xrightarrow{CH_3CH_2Br} CH_3CH_2C\equiv CCH_2CH_3$ (Y = hex-3-yne)