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In Friedel-Crafts reaction toluene can be prepared by :
A
$C_6H_6 + CH_3Cl$
B
$C_6H_5Cl + CH_4$
C
$C_6H_6 + CH_2Cl_2$
D
$C_6H_6 + CH_3COCl$
Detailed Solution
Friedel-Crafts alkylation: benzene reacts with an alkyl halide in the presence of anhydrous $AlCl_3$ to give an alkylbenzene.
$C_6H_6 + CH_3Cl \xrightarrow{anhyd.\ AlCl_3} C_6H_5CH_3 + HCl$
$AlCl_3$ generates the electrophile $CH_3^+$ (as a complex), which attacks the benzene ring.
With $CH_3COCl$, acylation gives acetophenone instead.
So toluene is prepared from $C_6H_6 + CH_3Cl$.
$C_6H_6 + CH_3Cl \xrightarrow{anhyd.\ AlCl_3} C_6H_5CH_3 + HCl$
$AlCl_3$ generates the electrophile $CH_3^+$ (as a complex), which attacks the benzene ring.
With $CH_3COCl$, acylation gives acetophenone instead.
So toluene is prepared from $C_6H_6 + CH_3Cl$.