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Given below are two statements: Statement I: trans-But-2-ene upon treatment with $Br_2$ in $CCl_4$ gives the following product.
Statement II: cis-But-2-ene upon treatment with alkaline $KMnO_4$ gives the following product.
In the light of the above statements, choose the most appropriate answer from the options given below.Detailed Solution
Anti addition of $Br_2$ to trans-but-2-ene gives the meso compound (2,3-dibromobutane). The product drawn in Statement I, on rotation to its staggered form, is optically active, so it is not the meso product - Statement I is incorrect. Syn dihydroxylation of cis-but-2-ene with alkaline $KMnO_4$ gives the meso diol (butane-2,3-diol); the product drawn in Statement II is the optically inactive meso form - Statement II is correct.