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The total number of $\pi$-bond electrons in the following structure is:
A
4
B
8
C
12
D
16
Detailed Solution
The structure has 4 C=C double bonds, i.e. 4 $\pi$ bonds.
Each $\pi$ bond has 2 electrons, so total $\pi$-bond electrons = 8.
Each $\pi$ bond has 2 electrons, so total $\pi$-bond electrons = 8.