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2-butene shows geometrical isomerism due to :
A
Restricted rotation about double bond
B
Free rotation about double bond
C
Free rotation about single bond
D
Chiral carbon
Detailed Solution
Rotation about a C=C double bond is restricted, because it would break the sideways overlap of p orbitals that forms the $\pi$ bond.
In 2-butene, $CH_3CH=CHCH_3$, each doubly bonded carbon carries two different groups (H and $CH_3$). So the two methyl groups can be on the same side (cis) or on opposite sides (trans), and these forms cannot interconvert.
So 2-butene shows geometrical isomerism due to restricted rotation about the double bond.
In 2-butene, $CH_3CH=CHCH_3$, each doubly bonded carbon carries two different groups (H and $CH_3$). So the two methyl groups can be on the same side (cis) or on opposite sides (trans), and these forms cannot interconvert.
So 2-butene shows geometrical isomerism due to restricted rotation about the double bond.