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The correct IUPAC name of the compound
is
is
A
3-(1-ethylpropyl)hex-1-ene
B
4-Ethyl-3-propylhex-1-ene
C
3-Ethyl-4-ethenylheptane
D
3-Ethyl-4-propylhex-5-ene
Detailed Solution
The structure is $CH_2=CH-CH(CH_2CH_2CH_3)-CH(CH_2CH_3)-CH_2-CH_3$.
The parent chain must be the longest chain that contains the double bond; it has six carbons, so the parent is hexene.
Numbering starts from the end nearer to the double bond, so the double bond is at C-1: hex-1-ene.
With this numbering there is a propyl group on C-3 and an ethyl group on C-4.
Substituents are written in alphabetical order (ethyl before propyl).
IUPAC name: 4-Ethyl-3-propylhex-1-ene