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Which of the following aqueous solution will exhibit highest boiling point?
A
$0.01\text{ M Urea}$
B
$0.01\text{ M KNO}_3$
C
$0.01\text{ M Na}_2\text{SO}_4$
D
$0.015\text{ M C}_6\text{H}_{12}\text{O}_6$
Explanation
Elevation in boiling point $\Delta T_b \propto i \times M$. For $\text{Na}_2\text{SO}_4$, $i \times M = 3 \times 0.01 = 0.03\text{ M}$, which is highest.
Detailed Solution
Boiling point elevation is a colligative property: $\Delta T_b = i \cdot K_b \cdot m \approx i \cdot K_b \cdot M$. Higher $i \times M$ results in a higher boiling point. Evaluating $i \times M$: (1) Urea: non-electrolyte, $i = 1 \implies 1 \times 0.01 = 0.01$. (2) $\text{KNO}_3$: dissociates into $\text{K}^+ + \text{NO}_3^-$ ($i = 2$) $\implies 2 \times 0.01 = 0.02$. (3) $\text{Na}_2\text{SO}_4$: dissociates into $2\text{Na}^+ + \text{SO}_4^{2-}$ ($i = 3$) $\implies 3 \times 0.01 = 0.03$. (4) Glucose: non-electrolyte, $i = 1 \implies 1 \times 0.015 = 0.015$. Since $0.01\text{ M Na}_2\text{SO}_4$ gives the largest total particle concentration ($0.03\text{ M}$), it exhibits the highest boiling point.
