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Mole fraction of the solute in a 1.00 molal aqueous solution is
A
1.7700
B
0.1770
C
0.0177
D
0.0344
Detailed Solution
A 1.00 molal aqueous solution contains 1 mole of solute in 1000 g of water.
Moles of water = $\frac{1000}{18} = 55.55$
Mole fraction of solute = $\frac{n_{solute}}{n_{solute} + n_{water}}$
$= \frac{1}{1 + 55.55} = \frac{1}{56.55}$
= 0.0177
Moles of water = $\frac{1000}{18} = 55.55$
Mole fraction of solute = $\frac{n_{solute}}{n_{solute} + n_{water}}$
$= \frac{1}{1 + 55.55} = \frac{1}{56.55}$
= 0.0177