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The right option for the mass of $CO_2$ produced by heating 20 g of 20% pure limestone is (Atomic mass of $Ca=40$): $CaCO_3\xrightarrow{1200\ K}CaO+CO_2$
A
1.32 g
B
1.12 g
C
1.76 g
D
2.64 g
The answer is C.
