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The amount of carbon dioxide evolved upon complete combustion of 116 g of n-butane is (Given: atomic mass in amu H = 1, C = 12 and O = 16)
Detailed Solution
n-butane is $C_4H_{10}$; $n=\frac{116}{58}=2$ mol. $C_4H_{10}+\frac{13}{2}O_2\rightarrow4CO_2+5H_2O$, so 2 mol butane gives 8 mol $CO_2$. Mass $=8\times44=352$ g.