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Equal masses of $H_2$, $O_2$ and methane have been taken in a container of volume V at temperature $27^\circ C$ in identical conditions. The ratio of the volumes of gases $H_2$ : $O_2$ : methane would be:
A
8 : 16 : 1
B
16 : 8 : 1
C
16 : 1 : 2
D
8 : 1 : 2
Detailed Solution
By Avogadro's hypothesis, volume ∝ moles.
$n_{H_2} = \frac{w}{2}$, $n_{O_2} = \frac{w}{32}$, $n_{CH_4} = \frac{w}{16}$
Ratio $= \frac{w}{2} : \frac{w}{32} : \frac{w}{16} = 16 : 1 : 2$
$n_{H_2} = \frac{w}{2}$, $n_{O_2} = \frac{w}{32}$, $n_{CH_4} = \frac{w}{16}$
Ratio $= \frac{w}{2} : \frac{w}{32} : \frac{w}{16} = 16 : 1 : 2$