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For given energy, $E = 3.03 \times 10^{-19}$ J, corresponding wavelength will be ($h = 6.6 \times 10^{-34}$ J s, $c = 3 \times 10^8$ m/s)
A
65.3 nm
B
6.53 nm
C
3.4 nm
D
653 nm
Detailed Solution
$E = \dfrac{hc}{\lambda} \Rightarrow \lambda = \dfrac{hc}{E}$
$\lambda = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{3.03 \times 10^{-19}} = \dfrac{19.8 \times 10^{-26}}{3.03 \times 10^{-19}}$
$\lambda = 6.53 \times 10^{-7}$ m $= 653$ nm
(This is red light in the visible region.)
$\lambda = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{3.03 \times 10^{-19}} = \dfrac{19.8 \times 10^{-26}}{3.03 \times 10^{-19}}$
$\lambda = 6.53 \times 10^{-7}$ m $= 653$ nm
(This is red light in the visible region.)