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Calculate the energy in joule corresponding to light of wavelength 45 nm: (Planck's constant h = $6.63\times10^{-34}$ Js; speed of light c = $3\times10^8$ $ms^{-1}$)
A
$6.67\times10^{15}$
B
$6.67\times10^{11}$
C
$4.42\times10^{-15}$
D
$4.42\times10^{-18}$
Detailed Solution
$E = \frac{hc}{\lambda} = \frac{6.63\times10^{-34}\times3\times10^8}{45\times10^{-9}}$
$E = 4.42\times10^{-18}$ J
$E = 4.42\times10^{-18}$ J
