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Match List - I (quantum number) with List - II (orbital). Choose the correct answer.
Column I
- A. $n=2$, $l=1$
- B. $n=3$, $l=2$
- C. $n=3$, $l=0$
- D. $n=2$, $l=0$
Column II
- I. 2s
- II. 3s
- III. 2p
- IV. 3d
Correct answer: A → III, B → IV, C → II, D → I
Detailed Solution
$l=0\Rightarrow s$, $l=1\Rightarrow p$, $l=2\Rightarrow d$. So $n=2, l=1\Rightarrow 2p$; $n=3, l=2\Rightarrow 3d$; $n=3, l=0\Rightarrow 3s$; $n=2, l=0\Rightarrow 2s$.