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In Freundlich Adsorption isotherm, the value of 1/n is:
A
1 in case of chemisorption
B
between 0 and 1 in all cases
C
between 2 and 4 in all cases
D
1 in case of physical adsorption
Detailed Solution
Freundlich adsorption isotherm: $\frac{x}{m} = kp^{1/n}$ (n > 1)
At low pressure $\frac{x}{m} \propto p^1$ and at high pressure $\frac{x}{m} \propto p^0$.
So the value of $\frac{1}{n}$ lies between 0 and 1.
At low pressure $\frac{x}{m} \propto p^1$ and at high pressure $\frac{x}{m} \propto p^0$.
So the value of $\frac{1}{n}$ lies between 0 and 1.