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Magnetic moment 2.83 BM is given by which of the following ions? (At. nos. Ti = 22, Cr = 24, Mn = 25, Ni = 28):
A
$Ti^{3+}$
B
$Ni^{2+}$
C
$Cr^{3+}$
D
$Mn^{2+}$
Detailed Solution
$\mu = \sqrt{n(n+2)} = 2.83$ BM gives n = 2.
$Ni^{2+}$ ($3d^8$) has two unpaired electrons.
$Ni^{2+}$ ($3d^8$) has two unpaired electrons.