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Which of the following elements exhibits maximum oxidation state :
A
Cr
B
Mn
C
Fe
D
V
Detailed Solution
The highest oxidation state of a first row transition element generally equals the total number of 3d and 4s electrons (up to Mn).
V ($3d^3\,4s^2$): +5; Cr ($3d^5\,4s^1$): +6; Mn ($3d^5\,4s^2$): +7 (as in $KMnO_4$); Fe: +6 (rare), usually +3.
So Mn exhibits the maximum oxidation state, +7.
V ($3d^3\,4s^2$): +5; Cr ($3d^5\,4s^1$): +6; Mn ($3d^5\,4s^2$): +7 (as in $KMnO_4$); Fe: +6 (rare), usually +3.
So Mn exhibits the maximum oxidation state, +7.