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In the neutral or faintly alkaline medium, $KMnO_4$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from
A
+6 to +5
B
+7 to +4
C
+6 to +4
D
+7 to +3
Detailed Solution
In neutral or faintly alkaline medium:
$KMnO_4 + I^- \rightarrow MnO_2 + IO_3^-$
Oxidation state of Mn changes from +7 (in $KMnO_4$) to +4 (in $MnO_2$).
