Question

It is because of inability of $ns^2$ electrons of the valence shell to participate in bonding that

Accepted Answer

$Sn^{2+}$ is reducing while $Pb^{4+}$ is oxidising

Answer

$Sn^{2+}$ is oxidising while $Pb^{4+}$ is reducing

Answer

$Sn^{2+}$ and $Pb^{2+}$ are both oxidising and reducing

Answer

$Sn^{4+}$ is reducing while $Pb^{4+}$ is oxidising

Explanation

Detailed Solution