Solution

BF3 has an incomplete octet on boron, so it accepts a lone pair.

$BF_3$ behaves as Lewis acid due to incomplete octet in valence shell of Boron. Hence it can accept a lone pair of electrons.

Concept BF3 as a Lewis acid

The p-Block Elements (Group 13 and 14) in past papers

9 questions from this chapter have appeared across 4 exam years.