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Aluminium chloride in acidified aqueous solution forms a complex 'A', in which hybridisation state of Al is 'B'. What are 'A' and 'B', respectively?
Detailed Solution
$AlCl_3$ in acidified aqueous solution forms $[Al(H_2O)_6]^{3+}$. $Al^{3+}$ = [Ne], with no inner d orbitals available, so it uses outer 3d orbitals: $sp^3d^2$.