A
Among halide ions, iodide is the most powerful reducing agent
B
Fluorine is the only halogen that does not show a variable oxidation state
C
HOCl is a stronger acid than HOBr
D
HF is a stronger acid than HCl
The answer is D.
Solution
Iodide is the most powerful reducing halide ion, since $I^-$ is the largest and loses its electron most easily (and $I_2$ is the weakest oxidant); true. Fluorine, the most electronegative element with no d orbitals, shows only the –1 state; true. In the hypohalous acids HOX, a more electronegative X pulls electron density from the O–H bond, so HOCl ($K_a \approx 3 \times 10^{-8}$) is stronger than HOBr; true. Among hydrogen halides, acid strength increases HF $\lt$ HCl $\lt$ HBr $\lt$ HI, because the H–X bond becomes weaker. The H–F bond is very strong and HF is a weak acid in water, while HCl is a strong acid. So the statement that is not true is: HF is a stronger acid than HCl.
ConceptAcid strength of hydrogen halides
The p-Block Elements in past papers
77 questions from this chapter have appeared across 23 exam years.