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Match List - I (Compounds) with List - II (Molecular formula). Choose the correct answer.
Column I
- A. Borax
- B. Kernite
- C. Orthoboric acid
- D. Borax bead
Column II
- I. $NaBO_2$
- II. $Na_2B_4O_7\cdot4H_2O$
- III. $H_3BO_3$
- IV. $Na_2B_4O_7\cdot10H_2O$
Correct answer: A → IV, B → II, C → III, D → I
Detailed Solution
Borax $\rightarrow Na_2B_4O_7\cdot10H_2O$; Kernite $\rightarrow Na_2B_4O_7\cdot4H_2O$; Orthoboric acid $\rightarrow H_3BO_3$; Borax bead $\rightarrow NaBO_2$ (with $B_2O_3$).