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Sulphur trioxide can be obtained by which of the following reaction:
A
$H_2SO_4 + PCl_5 \xrightarrow{\Delta}$
B
$CaSO_4 + C \xrightarrow{\Delta}$
C
$Fe_2(SO_4)_3 \xrightarrow{\Delta}$
D
$S + H_2SO_4 \xrightarrow{\Delta}$
Detailed Solution
$Fe_2(SO_4)_3 \xrightarrow{\Delta} Fe_2O_3 + 3SO_3$
$H_2SO_4 + PCl_5$ gives sulphuryl chloride/chlorosulphonic acid, $CaSO_4 + C$ gives $SO_2$ (or CaS), and $S + 2H_2SO_4 \rightarrow 3SO_2 + 2H_2O$.
So $SO_3$ is obtained by heating ferric sulphate.
$H_2SO_4 + PCl_5$ gives sulphuryl chloride/chlorosulphonic acid, $CaSO_4 + C$ gives $SO_2$ (or CaS), and $S + 2H_2SO_4 \rightarrow 3SO_2 + 2H_2O$.
So $SO_3$ is obtained by heating ferric sulphate.