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Given below are two statements:
Statement-I: Heating NaCl with concentrated $H_2SO_4$ and $MnO_2$ results in oxidation of Mn.
Statement-II: Heating NaI with concentrated $H_2SO_4$ and $MnO_2$ results in reduction of Mn.
In light of the above statements, choose the most appropriate answer from the options given below.
Detailed Solution
S-I: $4NaCl+MnO_2+4H_2SO_4\rightarrow MnCl_2+4NaHSO_4+2H_2O+Cl_2$. Mn goes from +4 to +2, i.e. it is reduced, not oxidised - Statement I is wrong. S-II: $2NaI+MnO_2+4H_2SO_4\rightarrow I_2+MnSO_4+Na_2SO_4+2H_2O$. Mn goes from +4 to +2, i.e. it is reduced - Statement II is correct.