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A compound is formed by two elements A and B. The element B forms cubic close packed structure and atoms of A occupy $\frac{1}{3}$ of tetrahedral voids. If the formula of the compound is $A_xB_y$, then the value of $x+y$ is in option
A
2
B
5
C
4
D
3
Explanation
4 B atoms and $\frac{8}{3}$ A atoms give $A_2B_3$, so $x+y=5$.
Detailed Solution
Since atom B forms CCP structure, there will be 4 B atoms.
Atom A occupies $\frac{1}{3}$ of tetrahedral voids; number of A atoms $=\frac{1}{3}\times8=\frac{8}{3}$
Formula of the compound $=A_{8/3}B_4=A_2B_3$
$x+y=2+3=5$