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If a is the length of the side of a cube, the distance between the body centered atom and one corner atom in the cube will be:
A
$\frac{2}{\sqrt3}a$
B
$\frac{4}{\sqrt3}a$
C
$\frac{\sqrt3}{4}a$
D
$\frac{\sqrt3}{2}a$
Detailed Solution
The body-centred atom lies at the middle of the body diagonal (length $\sqrt3a$).
Distance from the centre to a corner $= \frac{\sqrt3a}{2}$
Distance from the centre to a corner $= \frac{\sqrt3a}{2}$